Meteorologisk årbog - 01.01.1918, Síða 56

64
Januar Jacobshavn 1918
Hb = 12.6 m Cg = -f- 1.5 mm <p — 69° 13' N í — 510 2' W ht = 1.3 m hr = 1.9 m
Datum Date Barometer reduc. til 0° C. og 45 0 Br. Barométre á o° C. et lat. 45 0 700 mm -f- Temperatur Température c° Damptryk Tension de la vapeur d’eau mm Relativ Fugtighed Huniidité relative °/ /0 Vindens Retning og Styrke Direction et force du vent 0—12 Skydække Nébulosité 0- 10 3 Nedbor 5 Précipitation Anmærkninger Remarques
8“ 2P 9P 8a 2P 9P Max. Min. 8a 2» 9P 8a 2P 9P 8a 2 P 9P 8a 2P 9P 8a
| I 72.2 744 70.5 -19.0 -26.9 -19.5 -27.3 o-7 — 0.8 76 — 81 0 0 N 2 2 2 I
2 57H 54.2 59.1 -15.0 -I2.5 -IO.7 -27.3 I.I 1.6 1.8 77 92 90 O SE I SE I 7= 8 = 8 = -)fp =ma2p3
3 (64.0) (61.0) (58.0) — — — — — — — — — — — — — — — = n
4 64.7 71.8 78.7 -13.9 -I5.0 -23.5 -15-3 i-3 1.4 — 87 IOO — sw 8 sw 6 SE I 5* 3* O 5.8 n 1 a 2 p ^ p
5 75-5 76.2 79.6 -25.7 -27.1 -30.1 -28.3 — — — — — — NE I E I E I 2 0 0 5.2
6 77-4 74.1 71.; -25.1 -21.3 -16.9 -32.3 0.3 0.5 0.9 53 64 75 ESE I SE 2 SE I 6= 7= 8 = 1 a 2 p 3
7 64.7 58.6 5<5-5 -3-3 — I .1 -2.9 —21 -3 3-3 4.0 — 94 94 — SE 3 S 4 SW 5 8 = 8 = 8* 0.2 -)f n p° 3 0 ^ n 1 a 2 p
8 64.1 64.0 66.2 -20.9 -20.1 -22.3 -21.3 — 0.6 0-5 — 68 69 sw 6 sw 5 SE 2 5 = 7 = 2 ff°n ^nia2p
9 68.8 64.5 65.6 -27.7 -3O.2 -32.9 -29.3 0.3 — — 6> — — SE 3 SE 2 O ó== 6= O ^ n J a 2 p »/-*-y.
10 67.7 70.1 71.1 -33-5 -34.7 “35-1 -34-3 — — — — — ESE I 0 I 0 0 0 ^±=v
11 71-5 70.7 69.7 -33-3 -27.3 -27.9 -36.3 — 0.3 — — 55 — SE I E 1 E I 0 0 0
12 70.5 704 72.2 -33.1 -33-3 -28.5 “35-3 — — — — — — N I E 1 N I 0 0 0
13 73.8 72.6 72.6 -15-3 -15.1 “13-5 -34-3 1.0 1.1 1.2 72 77 80 NE 7 NE 5 E 7 1 0 0
14 7i.5 69.9 67.1 -n.9 -IO.9 -18.7 -17.3 1.6 1 -7 0.8 89 90 83 E 0 E 1 0 0 1 0
15 65.7 66.4 66.5 -20.9 -20.7 -20.3 -21.3 0.7 0.7 0.7 79 79 80 E I NE J 0 t 2 0
l6 67.5 66.5 64.5 -20.3 -22.7 -2/J.I -21.3 — 0.2 0.4 — 28 56 0 0 ESE I i 0 0
17 60.5 59-7 57-3 -25.1 -23.3 -18.9 -25-3 0.3 0.4 0.7 53 58 70 0 0 SE I 2 4= 6= = a2p 3
18 57-5 57-3 57-5 -17.9 -17.: -19.1 -25-3 0.9 1.0 — 84 84 — SE 2 SE 1 SE 4 7 — 8 = 7 = = n i a 2 p 3
19 57-7 57.2 55-6 -27.9 -28.1 -30.3 -28.3 0.3 — — 65 — — ESE 2 E 1 E I 3 I 0 =n
20 54.0 53.2 53-i -33-7 -34-5 “33-1 -34-3 E I SE 1 SE I 0 0 1 .
21 55-5 56.0 54.0 -36.3 -35-5 “34-7 -36.3 — — — - — — 0 0 0 0 2 1
22 50.8 50.J 48.5 -31.1 -31.3 -26.3 37.3 — — 0.4 — — 69 0 0 0 4 = 5 — 6= = n 1 a 2 p 3
23 47.0 48.1 52.5 -17.3 -1 I.I -24.3 -31-3 1.0 1.6 0.3 84 82 55 SE 0 S 3 SE I 7 = 6= 6 = = n 1 a 2 p 3
24 4«-9 48.0 47- -25.1 -26.7 -24.9 -27.3 °-3 0.4 0.4 53 68 72 NE I N 1 N 2 7 = 6r= I = n 1 a 2 p
25 48.6 50.6 51.2 -27.9 -33-7 “35-1 -29.7 0.3 — — 65 — — N 2 0 0 1 O 0 = na
26 53-9 54-8 54.6 -35- -28.3 -29.3 “35-9 — 0.3 — — 64 •- 0 0 0 1 5 0 = = na2p 3
27 53-9 5 3-5 53.8 -29.9 -28.9 -26.5 -35-3 — — 0.4 — — 69 0 0 0 0 0 3 = n
28 53-4 58.1 61.6 -15-3 -17.3 -10.3 -30.3 1.0 1.1 0.9 77 95 85 s I S 1 S 2 7 = 6 = 7 — = n 1 a 2 p 3
29 68.3 7-3 71.7 -26.3 -27.3 -3i-7 -26.5 0.4 0.3 — 69 66 — s 4 SE 1 0 5 = 2 0 = n 1 a
30 68.2 67.1 64.7 -34-7 -34-9 -35-i -35-3 — — — — — — SE I SE 1 O 0 0 0
31 Wl OO 4^ 55.8 (54-5) -3S-1 -33-9 “35-J -35-3 — — — — — — NE I SE 1 — 0 0 —
M. 62.3 62.1 62.2 -24.6 -24.4 —2 5 -0 -29.3 0.9 1.0 0.7 73 74 74 I •7 1.4 I 2 2.9 3.0 2.2 11.2
Februar 1918
I 49-3 48.7 45-9 -28.3 -18.5 -19.7 -35.5 0.2 0.9 0.9 52 83 94 0 0 ESE I 0 0 0
2 37-1 35-5 34.2 -23.9 -24.2 —2i-9j -29.1 0.4 0.4 0.4 56 64 02 ESE I 0 SE 2 5 — 3 1 11 i a
3 (434) 47.2 49.4 -j8.5 — J 8.7 -18.1 -26.3 0.5 0.8 0.9 49 83 84 0 0 0 0 0 0
4 49-5 49-6 49-7 -18.9 -l8.J -17.9 -25.3 0.8 0.8 0.9 82 72 84 S I 0 0 1 1 0
5 51.0 49.1 -J7-5 -1S.7 -18.5 -19.3 0.9 1.0 0.9 84 94 83 0 0 0 8s== 3= 2= = n : a 2 p 3
6 44.8 43-5 42.8 -6.7 -7-5 -9.1 -18.9 2-7 2-5 2.0 97 97 9' SE 4 SE 2 0 2 0 0 ==n
7 44.0 41.8 44-4 -18.7 -18.1 -17.1 -20.3 0.8 1.0 0.9 83 95 74 0 0 SE 2 3 == 2 4= = n i a p 3
8 494 49.6 53-2 -16.5 -20.3 -21.5 -20.3 1.0 0.7 0.6 85 80 78 S 4 SW 5 sw 6 7= 7 — ^ n r a 2 p 3
9 58.2 55-9 53-5 -28.1 -32.1 “33-3 -28.7 0.4 — — 88 — — SE I 0 0 3== 0 0 =n 1 a ./-X,
10 54.6 50.2 48.2 -20.3 -27.9 “IO.7 “35-3 0.8 0.3 j.9 93 53 97 0 E 3 N 3 0 2 0
11 47-S 48.7 45.8 -4-3 -4.9 “5-J -29.3 3-i 3-i — 93 98 — SE 3 SE 2 SE 6 7 = 5 = 5= ^ n 1 a 2 p 3
12 43.3 35.2 32.8 -2.5 -I.I -1.9 -5.8 3-7 — — 98 — — SE 5 SE 5 SE 7 6 = 4== 3 = ==ni a2p 3
J3 ‘dö.9 34.6 33.8 -3-5 -IO.3 -15.1 -3-3 — 1.8 — — 90 — SW 2 SW 4 SW 6 6= 8== 7 — ^ n 1 a 2 p 3
14 41.4 40.3 38.7 -19.1 —21.1 -26.4 —21.1 0.8 0.6 0.3 8l 79 59 E 3 E 4 E 4 3 2 0 = 11
13 35-3 37-5 42.0 -26.4 -22.9 -22.1 -26.8 0.3 0.5 0.6 59 76 77 0 SE 2 SE 3 0 5= 7=-- = 32p3
l6 45-5 41.3 43.0 -25.3 -27.I -30.3 -26.8 0.3 — — 53 — — E 3 E 1 0 2 0 0 = n
i (40.9) Í43-5) (44-4) — — | — — — — — — — — — — — —
18 (47-6) (47-0 (47-3) — — 1 — — — — — — — — — —
! 19 50.1 50.4 50.0 -30.7 -32.2 -347: -33-3 — — — — — — 0 o SE 1 0 0 5= = P 3
20 4S.2 47.2 46.6 -28.7 -28.1 -28.9 -34-9 0.3 — 0.4 62 — 87 SE 2 SE 1 SE 1 7 5= 7= ^ n 1 a 2 p 3
21 37.8 38.5 40.6 -27.1 -28.3 -32.3 -33-7 — 0.3 — — 64 — N 3 SE 2 0 5= 4^ 1 ^ n 1 a 2 p
22 42.0 47-9 49.9 -28.3 -27.7 -28.7 -35-3 — — 0.3 — — 62 E 1 SE 2 SE 1 4 = 5 = 5 — ^n 1 a 2 p 3
23 55-2 58.5 59-4 -31-3 -29. í -32.4 -32.3 — — — — — — SE I 0 0 1 0 5-s = np3
! 24 61.2 61.0 59-4 -31.3 -32.1 -32.5 “33-3 — — — — — — O 0 0 0 0 I = n
25 48.0 49.0 60.1 -32.7 -29.3 -3-3 -34-3 — — — — — — ESE 2 ESE 3 0 2 1 0
26 59-3 59-3 60.3 -30.7 -24.5 -25.1 -35-3 — 0.4 0.3 — 72 53 0 SSE 1 0 0 4= 5; = a2 p 3
27 52.9 42.9 39.8 -12.1 0.3 6.9 -32.3 J-7 4.2 4.8 96 90 65 N I N 3 SE 8 7— 7 = 8* •)fp3 = n 1 a 2 p 3
28 34.8 33-5 38.4 0.9 -i-3 -8.5 _13-3 4-5 2.3 90 97 SW I N 1 S 3 7= 8 4.2 •)f n =n j a2 p
M. 46.3 46.1 46.5 -20.4 -20.1 -20.6 -26.6 i-3 1.2 1.2 78 81 78 I 5 1.6 2 I 3-3 2.8 3.2 4.2