Jökull


Jökull - 01.12.1973, Side 24

Jökull - 01.12.1973, Side 24
//////////////////////////////////////////////^ o II 1- T = T0 o II f- 1 !i n m! //////////////////////////////////77/////7/77/Z////7//// x = 0 x=L/2 x = L Fig. 3. The strip model of a convection cell. the plane x = L/2; for an internally heated fluid, there is no condition at the median plane. There is negative buoyancy in the region Oíxí L/2; and positive buoyancy in the region L/2 x 5= L. Due to the insulation of the walls, the tem- perature will be constant transverse to the flow. Then, we need only solve a one-dimensional heat transport equation, to determine the temperature T(x) in the strip. Let the velocity u be the average velocity for steady laminar flow between rigid horizontal planes in the presence of a driving pressure gradient. For a Newtonian fluid, this velocity is given by (Lamb, 1932, p. 582). T2 dP 12tj dx (8) where dP/dx is the pressure gradient. We re- place (—dP/dx) by H/L' where H is the total head driving the flow, and L' is the fluid flow path length. This head results from the thermal expansion of the fluid and is given by H = pag [{ T(x)dx - J T(x)dx] L/2 0 (9) where T(x) is the temperature in the fluid. The length L in (9) must be identified with the length scale for heat conduction, i. e. L = 2h. The fluid flow length must be deter- mined from Fig. 2, resulting in ture T(x). In order to determine the total buoyant force this temperature distribution is then integrated over the length of the strip according to (9). Furthermore, equation (9) combined with the flow equation (8) yields an equation for the velocity u. As will be shown below, this equation has only the solution u = 0, unless a dimensionless number, the Ray- leigh number, exceeds a certain critical value. Thus the condition for the onset of thermal instability can be obtained on the basis of this relatively simple model. Despite the difference in approach, the simi- larities between the strip model and the Ray- leigh model should be emphasized. Both models assume laminar flow and neglect viscous dis- sipation and horizontal convection of heat. The strip model contains the additional simplifica- tions of (1) neglecting horizontal heat conduc- tion, (2) using an average flow velocity, (3) assuming the cell size on physical grounds. The essence of the two models is the same in that the flow is driven by buoyant forces aris- ing from the non-uniform density distribution and that convection occurs only if the Rayleigh number exceeds a certain critical value. Before discussing the problem of convection in two-phase systems we will demonstrate the application of the strip model in two cases which possess well-known solutions. The first case involves the homogeneous fluid layer heat- ed from below (Jeffreys, 1928) and the second a layer of an internally heated fluid (Roberts, 1967). APPLICATION TO A FLUID LAYER HEATED FROM BELOW For constant thermal conductivity and in the absence of heat sources, equation (7) reduces to d2T dT K--------ncu------= 0 (11) dx2 P dx v ' The boundary conditions are T(0) = T(L) = 0; T(L/2) = T0 (12) L' = \ + 2h —3T (10) The general method of solution with the strip model is to first determine the tempera- Due to the discontinuity of the heat flow at x = L/2, equation (11) must be solved separ- ately in the regions 0:?x:£L/2and L/2 5= xíLwe obtain 22 JÖKULL 23. ÁR
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